![]() When x and y are different objects that become the same value after the first step of Less than: x >= y is true, while x > y || x = y is false.JS Tutorial JS HOME JS Introduction JS Where To JS Output JS Statements JS Syntax JS Comments JS Variables JS Let JS Const JS Operators JS Arithmetic JS Assignment JS Data Types JS Functions JS Objects JS Events JS Strings JS String Methods JS String Search JS String Templates JS Numbers JS BigInt JS Number Methods JS Number Properties JS Arrays JS Array Methods JS Array Sort JS Array Iteration JS Array Const JS Dates JS Date Formats JS Date Get Methods JS Date Set Methods JS Math JS Random JS Booleans JS Comparisons JS If Else JS Switch JS Loop For JS Loop For In JS Loop For Of JS Loop While JS Break JS Iterables JS Sets JS Maps JS Typeof JS Type Conversion JS Bitwise JS RegExp JS Precedence JS Errors JS Scope JS Hoisting JS Strict Mode JS this Keyword JS Arrow Function JS Classes JS Modules JS JSON JS Debugging JS Style Guide JS Best Practices JS Mistakes JS Performance JS Reserved Words.When x and y are the same object that becomes NaN after the first step of Less than (such as new Date(NaN)): x >= y is false, while x = y is true.When one of x or y is undefined, and the other is one of null or undefined: x >= y is false, while x = y is true.When one of x or y is null, and the other is something that's not null and becomes 0 when coerced to numeric (including 0, 0n, false, "", "0", new Date(0), etc.): x >= y is true, while x > y || x = y is false. ![]() ![]() x >= y is generally equivalent to !(x = y and x = y is generally equivalent to x > y || x = y, except for a few cases: The operands are compared using the same algorithm as the Less than operator, with the result negated. Warning: unreachable code after return statement.Warning: -file- is being assigned a //# sourceMappingURL, but already has one.TypeError: X.prototype.y called on incompatible type.TypeError: setting getter-only property "x".TypeError: Reduce of empty array with no initial value.TypeError: property "x" is non-configurable and can't be deleted.TypeError: invalid assignment to const "x".TypeError: invalid 'instanceof' operand 'x'.TypeError: cannot use 'in' operator to search for 'x' in 'y'.TypeError: can't redefine non-configurable property "x".TypeError: can't delete non-configurable array element.TypeError: can't define property "x": "obj" is not extensible.TypeError: can't convert BigInt to number.TypeError: can't assign to property "x" on "y": not an object.TypeError: "x" is not a non-null object.Synta圎rror: Using to indicate sourceURL pragmas is deprecated.Synta圎rror: unterminated string literal.Synta圎rror: unparenthesized unary expression can't appear on the left-hand side of '**'.Synta圎rror: unlabeled break must be inside loop or switch.Synta圎rror: Unexpected '#' used outside of class body.Synta圎rror: test for equality (=) mistyped as assignment (=)?.Synta圎rror: redeclaration of formal parameter "x".Synta圎rror: missing = in const declaration.Unicode character class escape: \p after property list.Character class escape: \d, \D, \w, \W, \s, \S.Enumerability and ownership of properties.
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